A good answer might be:

Enter an integer:  1492                  OK
Enter an integer:  Fourteen ninety two   WRONG
Enter an integer:  14.92                 WRONG
Enter an integer:  -1492                 OK
Enter an integer:  1 4 9 2               WRONG

If the user enters one of the WRONG lines, the statement inData = stdin.readLine() will work without any problem. It will read in the characters the user typed and put them in the String object inData. However, the method parseInt in the statement num = Integer.parseInt( inData ) will not be able to understand the characters as an integer, and with throw an exception. The user will see something like:

Enter an integer:
14.92
java.lang.NumberFormatException: 14.92

The parseInt method is just one method of the wrapper class Integer. It should be used like this:

intVariable = Integer.parseInt( stringVariable );

QUESTION 17:

Could the following be interpreted as an integer?

"  84"