A good answer might be:

In terms of houseX, and houseW what is the X value of the center?
- center = houseX + houseW/2
In terms of the previous answer, and the width of the door, doorW, what is the X value of the left edge of the door, doorX ?
- doorX = center - doorW/2 = houseX + houseW/2- doorW/2

Calculating a Coordinate.

These calculations can be plugged into the final int declaration section of the applet:

import java.applet.Applet;
import java.awt.*;

// assume that the drawing area is 350 by 250
public class houseRectangles2 extends Applet
{
  final int width  = 350, height = 250;
  final int houseX =  65, houseY = 100, houseW = 110, houseH = 110 ;
  final int               doorY  = 165, doorW  =  25, doorH  =  40 ;
  final int lWindX =  90, lWindY = 115, lWindW =  30, lWindH =  30 ;
  final int rWindX = 130, rWindY = 115, rWindW =  30, rWindH =  30 ;
  final int trunkX = 255, trunkY = 100, trunkW =  10, trunkH = 100 ;

  final int doorX  = houseX + houseW/2 - doorW/2;
  
  public void paint ( Graphics gr )
  { 
     gr.setColor( Color.orange );    // there is no Color brown
     gr.drawRect( houseX , houseY , houseW, houseH); // house
     gr.drawRect( doorX  , doorY  , doorW , doorH ); // door
     gr.drawRect( lWindX , lWindY , lWindW, lWindH); // lwind
     gr.drawRect( rWindX , rWindY , rWindW, rWindH); // rwind
     gr.fillRect( trunkX , trunkY , trunkW, trunkH); // trunk
  }
}

Here is the revised picture that it produces:

If you see this, your browser is not running Java.

The same sort of calculation could be done with other points in the picture. The windows could be better centered, for example. But let's not bother. Instead, look at the graphpaper sketch again (click here to see it) and estimate (X, Y), the width, and the height for the rectangle containing the tree's foliage,

QUESTION 6:

Fill in the blanks:

X: _______________
Y: _______________
width: _______________
height: _______________

Click Here after you have answered the question