A good answer might be:

number += (number % 2 == 1 ) ? 1 : 0 ;

double discount;
char   code = 'B' ;

switch ( code )
{
  case 'A':
    discount = 0.0;
    break;

  case 'B':
    discount = 0.1;
    break;

  case 'C':
    discount = 0.2;
    break;

  default:
    discount = 0.3;
}

Often a program needs to make a choice among several options based on the value of a single expression. For example, a clothing store might offer a discount that depends on the quality of the goods:

• Class "A" goods are not discounted at all.
• Class "B" goods are discounted 10%.
• Class "C" goods are discounted 20%.
• anything else is discounted 30%.

To execute this fragment, look down the list of cases to match the value in code. The statment between the matching case and the next break is executed. All other cases are skipped. If there is no match, the "default" case is chosen.

Warning: the complete rules for switch statments are complicated. Read on to get the details.

QUESTION 5:

If code is 'C', what is the discount?