A good answer might be:

No.

Here is the example program modified to include a finally{} block. The catch{} for the NumberFormatException has been removed, so these exceptions will cause a jump out of the try{} block directly to the finally{} block.

import java.lang.* ;
import java.io.* ;

public class FinallyPractice
{
  public static void main ( String[] a ) throws IOException
  {
    BufferedReader stdin = 
        new BufferedReader ( new InputStreamReader( System.in ) );
    String inData; int num=0, div=0 ;

    try
    {
      System.out.println("Enter the numerator:");
      inData = stdin.readLine();
      num    = Integer.parseInt( inData );
      System.out.println("Enter the divisor:");
      inData = stdin.readLine();
      div    = Integer.parseInt( inData );
      System.out.println( num + " / " + div + " is " + (num/div) );
    }

    catch (ArithmeticException ex )
    {
      System.out.println("You can't divide " + num + " by " + div);
    }

    finally
    {
      System.out.println("If the division didn't work, you entered bad data." );
    }

    System.out.println("Good-by" );
  }
}

The user enters "Rats" and sees this output:

Enter the numerator:
Rats
If the division didn't work, you entered bad data.
Exception in thread "main" java.lang.NumberFormatException: Rats
        at java.lang.Integer.parseInt(Integer.java:409)
        at java.lang.Integer.parseInt(Integer.java:458)
        at FinallyPractice.main(FinallyPractice.java:16)

QUESTION 15:

Where did the last 4 lines of output come from?