File progFile = new File( "C:\MyFiles\Programs\Examples\someFile.txt" );

A good answer might be:

Yes.

When a File object is constructed, no check is made to see if the pathName corresponds to an existing file or directory. If a file or directory of pathName does not exist, constructing a File object will not create it.

Here is an example program that constructs a File object and uses one of its methods. The constructor argument is a simple file name (which counts as a relative path name).

import java.io.*;
class testExist
{

 public static void main ( String[] args ) 
 {
   String pathName = "notLikely.txt" ;

   File   test = new File( pathName );

   if ( test.exists() )
     System.out.println( "The file " + pathName + " exists." );
   else
     System.out.println( "The file " + pathName + " Does Not exist." );
 }

}

The program can be copied to a file, compiled, and run. Since pathName is a simple file name the File object will use the current directory.

QUESTION 4:

What will the program probably print on the monitor?